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-36x^2+51x-18=0
a = -36; b = 51; c = -18;
Δ = b2-4ac
Δ = 512-4·(-36)·(-18)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-3}{2*-36}=\frac{-54}{-72} =3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+3}{2*-36}=\frac{-48}{-72} =2/3 $
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